Question

What is an equation of the line that passes through the point (-3,-1) and is

perpendicular to the line x - 2y = 62

Answer 1

y = -2x - 7

Explanation:

x - 2y = 6

-2y = -x + 6

Divide the whole equation by (-2)

`(-2y)/(-2)=(-x)/(-2)+(6)/(-2)\\\\y = (1)/(2)x - 3`

slope = 1/2

Slope of the line perpendicular to this line = -1/m = -1 ÷ (1/2)

`=(-1)*(2)/(1)\\\\= -2`

(-3, - 1)

y -y1 = m(x -x1)

y - [-1] = -2(x - [-3])

y + 1 = -2(x + 3)

y + 1= x* (-2) + 3*(-2)

y + 1 = -2x - 6

y = -2x - 6 - 1

y = -2x - 7