Answer:
-3
-7/3
Explanation:
Let u=x+2
We need to now solve 3u^2+4u+1=0 for u.
I'm going to try factoring. 3u (u)=3u^2 and 1(1)=1 so I'm going to try factored form (3u+1)(u+1).
Since 3u(1)+1(u)=4u, we are done.
Since (3u+1)(u+1)=0, then either 3u+1=0 or u+1=0.
Let's solve u+1=0 by subtracting 1 on both sides which obtains for us that u=-1.
Let's solve 3u+1=0 by subtracting 1 and then dividing both sides by 3 which obtains for us u=-1/3.
Since u=x+2, we are down to just solving the following:
x+2=-1 and x+2=-1/3
Both equations require us to subtract 2 on both sides.
The solutions are
x=-1-2=-3 and x=-1/3-2=-7/3