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Which answer represents the series in sigma notation? 1+12+14+18+116+132+164 ∑j=1712(j+1) ∑j=17(12)j−1 ∑j=1712j+1 ∑j=172j−1

Which answer represents the series in sigma notation? 1+12+14+18+116+132+164 ∑j=1712(j+1) ∑j=17(12)j−1 ∑j=1712j+1 ∑j=172j−1
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Which answer represents the series in sigma notation?

1+12+14+18+116+132+164




∑j=1712(j+1)

∑j=17(12)j−1

∑j=1712j+1

∑j=172j−1

User Michael Wheeler
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8.8k points

1 Answer

12 votes

Answer: The answer is the second one: ∑j=17(12)j−1

Explanation:

User Ethan Vu
by
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