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40 votes
40 votes
Factorize :solve no g and h ​

Factorize :solve no g and h ​-example-1
User Rivkah
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2 Answers

15 votes
15 votes

Answer:

here only one formula to use in both question

a^2+b^2= (a+b)(a-b)

Factorize :solve no g and h ​-example-1
User Alternatex
by
2.9k points
14 votes
14 votes

Answer:

Hello,

do you mean factorise but not solve ?

Just one formula:


\boxed{a^2-b^2=(a-b)(a+b)}

Explanation:


g)\\\\16x^3y-81xy^5\\\\=xy(16x^2-81y^4)\\\\=xy(4x^2+9y^2)(4x^2-9y^2)\\\\=xy(2x-3y)(2x+3)(4x^2+9y^2)\\\\\\\\h)\\\\x^8-y^8\\\\=(x^4+y^4)(x^4-y^4)\\\\=(x^4+y^4)(x^2+y^2)(x^2-y^2)\\\\=(x-y)(x+y)(x^2+y^2)(x^4+y^4)\\

User JDupont
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2.5k points