Question

Please help URGENT!!... There are 200 students in the 7th grade class at Manchester Middle School. Of these students, 22% play football, and 12% play baseball. Eight students play on both teams. What is the probability that a student plays either football or baseball? A. 30% B. 38% C. 26% D. 34%

Answer 1

Answer:34

Step-by-step explanation:just add the percents

Answer 2

C. 26%

Explanation:

We can sort students into three categories: Football Only, Baseball Only, and students who play Both.

Firstly, let's turn the percentages into numbers to make the calculations easier:

To find 22% convert into decimal and multiply:

0.22 x 200 = 44 TOTAL Football players

Similarly, 0.12 x 200 = 24 TOTAL Baseball players.

The question then tells us that 8 students play both.

This means there are 44-8 = 36 students who play ONLY football, and

24-8= 16 students who ONLY play baseball:

Football Only: Both: Baseball Only:

36 8 16

44 Total Football and 24 total baseball

The question asks the probability of a student playing EITHER football OR baseball which therefore does not include the students who play both.

Now we can add up all these numbers of students which gives us:

36 + 16 = 52

Now to find the percentage we just divide 52 by 200:

52/200 = 0.26 which is equivalent to 26%.

Therefore the answer is C. 26%

Hope this helped!