Question

Find 2 consecutive odd integers sum of who's square is 290​ pls send fast

Answer 1

Hence required integers are 11 and 13

Let x an odd positive integer

Then, according to question

x^2 +(x+2)^2=290

2x^2 +4x−286=0

x^2 +2x−143=0

x ^2+13x−11x−143=0

(x+13)(x−11)=0

x=11 as x is positive

Hence required integers are 11 and 13

Explanation:

Hope it is helpful....