Question

A spinner marked A, B, C is spun then a 6-sided die is rolled. What is the probability of getting a B and then a 6.

131 third

161 sixth

1121 over 12

118

Answer 1

Given:

A spinner marked A, B, C is spun then a 6-sided die is rolled.

To find:

The probability of getting a B and then a 6.

Solution:

We know that,

`\text{Probability}=\frac{\text{Favorable outcomes}}{\text{Total outcomes}}`

Total possible values for a spinner are 3. So, the probability of getting B, we get

`P(B)=(1)/(3)`

Total possible values for a die are 6. So, the probability of getting 6, we get

`P(6)=(1)/(6)`

Now, the probability of getting a B and then a 6 is

`P(B,6)=(1)/(3)* (1)/(6)`

`P(B,6)=(1)/(18)`

The required probability is
`(1)/(18)`.

Therefore, the correct option is D.