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37 votes
37 votes
A pendulum is swinging next to a wall. The distance D(t)D(t)D, left parenthesis, t, right parenthesis (in \text{cm}cmstart text, c, m, end text) between the bob of the pendulum and the wall as a function of time ttt (in seconds) can be modeled by a sinusoidal expression of the form a\cdot\sin(b\cdot t)+da⋅sin(b⋅t)+da, dot, sine, left parenthesis, b, dot, t, right parenthesis, plus, d. At t=0t=0t, equals, 0, when the pendulum is exactly in the middle of its swing, the bob is 5\text{ cm}5 cm5, start text, space, c, m, end text away from the wall. The bob reaches the closest point to the wall, which is 3\text{ cm}3 cm3, start text, space, c, m, end text from the wall, 111 second later. Find D(t)D(t)D, left parenthesis, t, right parenthesis. \textit{t}tstart text, t, end text should be in radians.

User HenryAdamsJr
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2 Answers

17 votes
17 votes

Answer:

-2sin(pi/2 t)+5

Explanation:

ALso did on Khan Academy (its on the sinisoidal equations excercise)

User Vincent G
by
3.0k points
14 votes
14 votes

Answer:

D(t)=-2sin(pi/2 t)+5

Explanation:

i did it on Khan academy

User Hosseio
by
3.2k points