Question

Factorize 27a³-b³-1-9ab

Answer 1

Hope this helps!

Please see through the steps below

Answer 2

Use the following identity:

• a³ + b³ + c³ - 3abc = (a + b + c)(a² + b² + c²- ab - bc - ca)

Apply to the given:

• 27a³ - b³ - 1 - 9ab =
• (3a)³ + (-b)³ + (-1)³ - 3*3a*(-b)(-1) =
• (3a - b - 1)(9a² + b² + 1 + 3ab - b + 3a)