Question

Find the cost of the painting of a rectangular box of length 6m breadth 4m and height 3m at the rate of rs.25 per meter square

I really need this ​

Answer 1

Answer:Rs.2700

Step-by-step explanation:step1is 2[6*3]+2[6*4]=84

step2is 2[3*4]=24

24+84=108*25=2700

Answer 2

G I V E N :

find the cost of the painting of a rectangular box of length 6m breadth 4m and height 3m at the rate of rs.25 per meter square

S O L U T I O N :

According to the question, first we need to get the T.S.A. or Total Surface Area of the cuboid then dividing it by ₹ 0.25 we can get the cost. After solving the concept will be more clear.

Let's start :

• T.S.A = 2(lb + bh + hl)

Here,

l represents length

b represents breadth

h represents height

Now, putting the values of all these we get

• T.S.A. = 2(6 × 4 + 4 × 3 + 3 × 6)

• T.S.A. = 2(24 + 12 + 18) m²

• T.S.A. = 2(54) m²

• T.S.A. = 108 m²

Now, we are given that cost of every square metre costs ₹ 0.25

So, for 108 m² it will cost = ₹ 108 × 0.25 = ₹ 27

Hence, cost of painting the rectangular box is ₹ 27