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K(k + 1)(k + 2) – 3k(k + 1)

Need a step-by-step guide on how to factor this completely

User Stilgar
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1 Answer

14 votes

Answer:

Explanation:

k(k+1)(k+2) - 3k(k+1)

k and (k+1) are common to both terms.

k(k+1)(k+2) - 3k(k+1) = k(k+1)[(k+2) - 3] = k(k+1)(k-1)

User Michal Dymel
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