393,768 views
20 votes
20 votes
Can someone help me find the standard deviation of this data set plssss

35
27
24
42
25
31
41
34
32
46
29
44
29
35
39
27
41
63
52
31
38
46
39
27
58
32
33
47
36
28
65
53
40
32
39
44
48
59
46
62
22
39
35
29
36
66
33
45
50
62
27
27
41
33
54
44
26
31
45
33
42
63
51
70
42
53
38
28
35
49
47
54
44
40
39
62
30
35
38
26
34
61
19
30
34
26
41
35
26
54
28
32
50
27
31
35
38
26
47
30
28
62
57
56
30
32
31
36
32
42
33
51
35
30
28
20
23
27
33
36
35
42
43
28
36
44
58
41
36
37
49
34
23
39
34
37
62
23
28
26
29
30
37
46
43
56
53
31
36
44
39
51
21
51
34
30
25
31
38
52
49
43
50
31
36
32
28
44
61
57
24
63
28
31
32
26
28

User Bilal
by
2.8k points

2 Answers

16 votes
16 votes

since it was too long, I just made this python code in order to solve for it:

from math import *

data = [35, 27, 24, 42, 25, 31, 41, 34, 32, 46, 29, 44, 29, 35, 39, 27, 41, 63, 52, 31, 38, 46, 39, 27, 58, 32, 33, 47, 36, 28, 65, 53, 40, 32, 39, 44, 48, 59, 46, 62, 22, 39, 35, 29, 36, 66, 33, 45, 50, 62, 27, 27, 41, 33, 54, 44, 26, 31, 45, 33, 42, 63, 51, 70, 42, 53, 38, 28, 35, 49, 47, 54, 44, 40, 39, 62, 30, 35, 38, 26, 34, 61, 19, 30, 34, 26, 41, 35, 26, 54, 28, 32, 50, 27, 31, 35, 38, 26, 47, 30, 28, 62, 57, 56, 30, 32, 31, 36, 32, 42, 33, 51, 35, 30, 28, 20, 23, 27, 33, 36, 35, 42, 43, 28, 36, 44, 58, 41, 36, 37, 49, 34, 23, 39, 34, 37, 62, 23, 28, 26, 29, 30, 37, 46, 43, 56, 53, 31, 36, 44, 39, 51, 21, 51, 34, 30, 25, 31, 38, 52, 49, 43, 50, 31, 36, 32, 28, 44, 61, 57, 24, 63, 28, 31, 32, 26, 28]

def stand_dev(list_n):

x = 0

sum_num = 0

for x in list_n:

sum_num += list_n[x]

sum_of_n = sum_num

mean = float(sum_of_n / len(list_n))

float(mean)

i = 0

e = 0.0

for i in list_n:

subtract_then_square = (list_n[i] - mean)**2

e += subtract_then_square

result1 = e

new_mean = result1 / len(list_n)

final_result = float(sqrt(new_mean))

return final_result

print(stand_dev(data))

basically, the first chunk of the code calculated the mean of the data. The second chunk would take all of the values from the data, subtract it from the mean, and then square it. I then took the sum of all the new values and average it to get the new mean, then square rooted the new mean to get the answer.

it should be ~= 11.713, but you can always check it by searching up a python compiler online and then insert in the data.

User PythEch
by
3.2k points
20 votes
20 votes

Answer:

I used MS excel and got the attached results.

Note the data is sorted and the data size is 177.

The answer I got is 11.31045226

Can someone help me find the standard deviation of this data set plssss 35 27 24 42 25 31 41 34 32 46 29 44 29 35 39 27 41 63 52 31 38 46 39 27 58 32 33 47 36 28 65 53 40 32 39 44 48 59 46 62 22 39 35 29 36 66 33 45 50 62 27 27 41 33 54 44 26 31 45 33 42 63 51 70 42 53 38 28 35 49 47 54 44 40 39 62 30 35 38 26 34 61 19 30 34 26 41 35 26 54 28 32 50 27 31 35 38 26 47 30 28 62 57 56 30 32 31 36 32 42 33 51 35 30 28 20 23 27 33 36 35 42 43 28 36 44 58 41 36 37 49 34 23 39 34 37 62 23 28 26 29 30 37 46 43 56 53 31 36 44 39 51 21 51 34 30 25 31 38 52 49 43 50 31 36 32 28 44 61 57 24 63 28 31 32 26 28-example-1
Can someone help me find the standard deviation of this data set plssss 35 27 24 42 25 31 41 34 32 46 29 44 29 35 39 27 41 63 52 31 38 46 39 27 58 32 33 47 36 28 65 53 40 32 39 44 48 59 46 62 22 39 35 29 36 66 33 45 50 62 27 27 41 33 54 44 26 31 45 33 42 63 51 70 42 53 38 28 35 49 47 54 44 40 39 62 30 35 38 26 34 61 19 30 34 26 41 35 26 54 28 32 50 27 31 35 38 26 47 30 28 62 57 56 30 32 31 36 32 42 33 51 35 30 28 20 23 27 33 36 35 42 43 28 36 44 58 41 36 37 49 34 23 39 34 37 62 23 28 26 29 30 37 46 43 56 53 31 36 44 39 51 21 51 34 30 25 31 38 52 49 43 50 31 36 32 28 44 61 57 24 63 28 31 32 26 28-example-2
User IrAM
by
3.3k points
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