Answer:
g(1)=-72; g(n)=g(n-1)*(1/6)
Explanation:
g(1)= -72*(1/6)^(1-1)=-72*(1/6)^0=-72*1=-72
g(2)=-72*(1/6)^(2-1)=-72*(1/6)^1=-72*(1/6)=-12
g(2)=g(1)*(1/6)
g(n)=g(n-1)*(1/6)
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