Question

please help with maths work

Answer 1

Given:

In a right angle triangle ABC,
`\angle B=90^\circ,x=8.7\ m`, and
`\theta = 45^\circ`

To find:

The value of AC.

Solution:

In a right angle triangle,

`\cos \theta =(Adjacent)/(Hypotenuse)`

`\cos \theta =(BC)/(AC)`

`\cos (45^\circ) =(8.7)/(AC)`

`(1)/(√(2))=(8.7)/(AC)`

On cross multiplication, we get

`AC=8.7* √(2)`

`AC=12.30365799`

`AC\approx 12.304`

Therefore, the measure of AC is 12.304 m.