Question

The spinner shown is divided into equal sections that each contain one number, so that the probability of spinning each number on the spinner is the same. However, there are two red sections, and therefore there are a total of two numbers (1 and 3) that appear in red sections, while each other color appears in only one section.

A spinner with 6 equal-sized sections labeled 1 through 6. Sections 1 and 3 are red. Section 2 is blue. Section 4 is orange. Section 5 is purple. Section 6 is green.
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What is the value of P(x:x is a red section)?

Enter your answer as a fraction in simplest terms, using the / symbol. For example, if your answer is 4284, which reduces to 12, enter it like this: 1/2

Answer 1

The probability of spinning a red section is 1/3.

In this scenario, there are two red sections out of a total of six. Therefore, the probability (P) of spinning a red section is:

P(x: x is a red section) = 2 red sections / 6 total sections

Simplifying the fraction, we get:

P(x: x is a red section) = 1/3

Therefore, the probability of spinning a red section is 1/3.

Answer 2

the answer is 2/6 im not sure but i hope its help