Question

For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 8 N acts on a certain object, the acceleration of the object is 4 m/s?. If the acceleration of the object becomes 3 m/s?, what is the force?

Answer 1

F = 6N

Explanation:

Equation

F = ka

F - force

k - constant of proportionality

a - acceleration

Step 1 - find k

8N=k*4m/s^2

k=2

Step 2 - find F

F=2*3m/s^s

F=6

Answer 2

Here Mass is constant

• F1=8N
• a_1=4m/s^2
• a_2=3m/s^2
• F_2=?

Using Newtons s law

`\\ \sf \longmapsto F=ma`

`\\ \sf \longmapsto (F)/(a)=m`

`\\ \sf \longmapsto (F_1)/(a_1)=(F_2)/(a_2)`

`\\ \sf \longmapsto (8)/(4)=(F_2)/(3)`

`\\ \sf \longmapsto F_2=(24)/(4)`

`\\ \sf \longmapsto F_2=6N`