Answer:
Explanation:
I think the best way to do this is to find B using the cos law. The two other angles are equal
b = 3sqrt(3)
a = 3
c = 3
b^2 = a^2 + b^2 - 2ab*cos(B)
(3sqrt(3)^2 = 3^2 + 3^2 - 2*3*3 * cos(B)
27 = 9 + 9 - 18*cos(B)
27 = 18 - 18*cos(B)
9 = - 18*cos(B)
9/-18 = cos(B)
-1/2 = cos(B)
B = cos-1(-1/2)
B = 120
<A + <C + 120 = 180
<A = <C
2A + 120 = 180
2A = 60
A = 30
The question says angle A so that's what I did.