Question

If h(x) = x2-5x + 7 find:
⅓ h(-8)

Answer 1

1/3 (h(-8)) = 37. hope this helped

Answer 2

`\displaystyle (1)/(3) h(-8) = 37`

Explanation:

Hi there!

`h(x) = x^2-5x + 7`

First, find h(-8) by replacing all of
`x` with -8:

`h(-8) = (-8)^2-5(-8) + 7\\h(-8) = 64+40 + 7\\h(-8) = 111`

Now, find ⅓ h(-8) by multiplying the entire expression by ⅓:

`\displaystyle (1)/(3) h(-8) = 111 * (1)/(3) \\\\\displaystyle (1)/(3) h(-8) = 37`

I hope this helps!