Question

STEP BY STEP PLEASE

If the perimeter of square 3 is 36 units and the perimeter of square 2 is 48 units, what is the area of square 1?

Answer 1

225

Explanation:

length of side in square 3 = 36/4

=9

length of side in square 2 = 48/ 4

= 12

using pythagorus theorem you can find side of square 1

take the triangle between 3 and 2

9^2 + 12^2 = length of side 1^2

81 + 144 = l^2

225 = l^2

l = 15

therefore length of side 1 is 15

area of square 1 = 15^15

area = 225 square units

hope this helped

ask if you didn't understand something or you think i am wrong:)

Answer 2

We can find the side length of square 3 by dividing by 4, which is 9.

Then, we find the side length of square 2 by dividing it by 4, which is 12.

To find the AREA of square 1, we do a^2+b^2=c^2. This is basically adding up area of square 1 and square 2 to get square 3.

a^2+b^2=c^2
9^2+12^2=c^2
81+144=225

So the area is 225 units.