Answer:
The end velocity of the sculpture is 7.00 m/s²
Step-by-step explanation
The equation needed here is v = √(2gh). Let's do it:
v = √(2 × 9.8m/s² × 2.5m)
v = √(49.0 m²/s²)
v = 7.0m/s
Funny enough the numbers given don't have the accuracy demanded. We're given is 2.5m which is only accurate to the tenths, and 30kg which is only accurate to the nearest integer. Also, presumably the acceleration due to Earth gravity that's provided is only 9.8m/s², so that's still only the nearest tenth. So taking those and asking to find the answer to the nearest hundredth is pointless.
But whatever. The given answer is correct to the nearest hundredth. 7.00m/s² To be sure, I plugged it into a form on a physics page that does exactly that, and the answer they gave was 7.0023745972349, so we have it rounded correctly.