Question

The current in the wires of a circuit is 60.0 milliAmps. If the

voltage impressed across the ends of the circuit were
doubled and the resistance were tripled, then its new current
would be ___ milliAmps.

Answer 1

I' = 40 mA

Step-by-step explanation:

Given that,

The current in the wires of a circuit is 60.0 mA.

If the voltage impressed across the ends of the circuit were doubled and the resistance were tripled such that,

V' = 2V and R'=3R

The relation between current, voltage and resistance is given by :

V = IR

Let I' be the new current. So,

V'=I'R'

⇒
`I'=(V')/(R')\\\\I'=(2V)/(3R)\\\\I'=(2)/(3)* (V)/(R)\\\\I'=(2)/(3)* I\\\\I'=(2)/(3)* 60\\\\I'=40\ mA`

So, the new current would be 40 mA.