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A 1000 kg truck moving at 2.0 m/s runs into a concrete wall. It takes 0.5 s for the truck to completely stop. What is the magnitude of force exerted on the truck during the collision?​

1 Answer

9 votes

Answer:

Momentum is given by

p

=

m

v

. Impulse is the change of momentum,

I

=

Δ

p

and is also equal to force times time:

I

=

F

t

. Rearranging,

F

=

I

t

=

Δ

p

t

=

0

20

,

000

5

=

4000

N

.

Step-by-step explanation:

Momentum before the collision is

p

=

m

v

=

2000

10

=

20

,

000

k

g

m

s

1

.

Assuming the truck comes to a complete halt, the momentum after the collision is

0

k

g

m

s

1

.

The change in momentum,

Δ

p

, is initial minus final

0

20

,

000

=

20

,

000

This is called the impulse:

I

=

Δ

p

. Impulse is also equal (check the units) to force times time:

I

=

F

t

.

We can rearrange this expression to make

F

the subject:

F

=

I

t

=

Δ

p

t

=

20

,

000

5

=

4000

N

The negative sign just means the force acting is in the opposite direction to the initial momentum.

(This will be the average force acting during the collision: collisions are chaotic so the force is unlikely to be constant.)

User Swogger
by
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