66,031 views
5 votes
5 votes
A game involves correctly choosing the 5 correct numbers from 1 through 18 that are randomly drawn. What is the probability that a person wins the game, if they enter a) once? b) 7 times with a different choice each time?

User Nkchandra
by
2.6k points

1 Answer

11 votes
11 votes

Answer:


=(1)/(8568)\ = .00011\\\ =(7)/(8568) = .00081

Explanation:


5/18\cdot \:4/17\cdot \:3/16\cdot \:2/15\cdot \:1/14=(1)/(8568)

User Baer
by
2.5k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.