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(c^3b^1a^4)^4 + 3a^16b^4c^12

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(c^3b^1a^4)^4 + 3a^16b^4c^12

asked Dec 10, 2022 51.7k views

1 vote

(c^3b^1a^4)^4 + 3a^16b^4c^12

Mathematics
high-school

GrayedFox asked

8.2k points

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1 Answer

9 votes

Answer: 4a16b4c12

Explanation:

Heitor Castro answered Dec 17, 2022

by Heitor Castro

8.1k points

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