Question

Factorize. xy^2-y(x-z) -z​

Answer 1

The equation x

The equation x 2

The equation x 2 +xy+xz+yz can be factorised as follows:

The equation x 2 +xy+xz+yz can be factorised as follows:x

The equation x 2 +xy+xz+yz can be factorised as follows:x 2

The equation x 2 +xy+xz+yz can be factorised as follows:x 2 +xy+xz+yz=(x

The equation x 2 +xy+xz+yz can be factorised as follows:x 2 +xy+xz+yz=(x 2

The equation x 2 +xy+xz+yz can be factorised as follows:x 2 +xy+xz+yz=(x 2 +xy)+(xz+yz)=x(x+y)+z(x+y)=(x+z)(x+y)

The equation x 2 +xy+xz+yz can be factorised as follows:x 2 +xy+xz+yz=(x 2 +xy)+(xz+yz)=x(x+y)+z(x+y)=(x+z)(x+y)Hence, x

The equation x 2 +xy+xz+yz can be factorised as follows:x 2 +xy+xz+yz=(x 2 +xy)+(xz+yz)=x(x+y)+z(x+y)=(x+z)(x+y)Hence, x 2

The equation x 2 +xy+xz+yz can be factorised as follows:x 2 +xy+xz+yz=(x 2 +xy)+(xz+yz)=x(x+y)+z(x+y)=(x+z)(x+y)Hence, x 2 +xy+xz+yz=(x+z)(x+y)

Answer 2

= (y-1) (xy-z)

Explanation:

First we expand them -

= xy^2 - xy - yz - z

= xy(y-1)-z(y-1)

= (y-1) (xy-z)

Hope this helped