Question

(Help would be greatly appreciated) What is the molarity of a solution made from 325.4g of AlCl3 with enough water to make 500.0mL?

1. 4.88g
2. 4.88M
3. 2.440M
4. 2.44M

Answer 1

4.88 M

Step-by-step explanation:

M = number moles/Volume (L)

MM AlCl3 = 133.34 g/mol

Volume = 500 mL = 0.5 L

number moles = mass/MM = 325.4/133.34 = 2.44 moles AlCl3

M = 2.44/0.5 = 4.88 M