Question

What is an equation of the line that passes through the point (-4,3) and is

perpendicular to the line 4x – 5y 20?

Answer 1

y=-5x/4-2

Explanation:

4x – 5y = 20

y = (4/5)x - 4

slope is 4/5

let new slope m:

(m)(4/5)=-1

m=-5/4

point slope form:

(y-3)/(x+4)=-5/4

y-3=-5x/4-5

y=-5x/4-2