Question

HELP PLEASE!

The length of a rectangle is 2V5. The width of the same rectangle is 5V5. Find the perimeter and area of the rectangle.

Answer 1

Area=5rad5 times 2rad5 equals 50 Bc rad 5 times rad 5 is rad 25 or 5 and 2 timers 5 is ten so now it is 5 times 10=50

Answer 2

Answers:

`\text{Perimeter} = 14√(5)\\\\\text{Area} = 50\\\\`

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Work Shown:

`L = 2√(5) = \text{length}`

`W = 5√(5) = \text{width}`

P = perimeter

`P = 2*(L+W)\\\\P = 2*(2√(5)+5√(5))\\\\P = 2*(7√(5))\\\\P = 14√(5)\\\\`

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A = area

`A = L*W\\\\A = (2√(5))*(5√(5))\\\\A = (2*5)(√(5)*√(5))\\\\A = 10√(5*5)\\\\A = 10√(25)\\\\A = 10*5\\\\A = 50\\\\`