Question

A ball is tossed upwards into the air with an initial upwards velocity of 3.0m/s. What is the ball's velocity when it returns to the height from which it was tossed?

Answer 1

Answer :

Explanation : h =v²/2g
h =9m²/s²/20m/s²
h = 0.45 m

Answer 2

• Initial velocity=u=3.0m/s
• Acceleration due to gravity=g=9.8m/s^2

Neglate air resistance.

• So acceleration is unchanged
• As acceleration is remaining constant so at the top the velocity is 0.
• But at the end the velocity again come to 3m/s.