Answer:
see attached
Explanation:
The left piece is a little tricky because it does not intersect the y-axis. You know it has a slope of -1, so it will be 1 unit higher than the y-intercept when it is 1 unit left of the y-axis. It ends at (-1, 3). The end point is not included in the definition of the relation, so an open circle is shown.
The right piece crosses the y-axis at y=-3, and has a slope of 2. It ends at (-1, -5). This end point is included, so a solid dot will be found at (-1, -5).
The relation is doubly-defined at x = -1, so there is another solid dot at (-1, -2).
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Additional comment
It is incorrect to call this a function, because it fails the vertical line test at x = -1. There are two points on that vertical line. (You may want to discuss this question with your teacher.)