Question

Physics help, thank you guys so much!

Answer 1

Δt = 5.85 s

Step-by-step explanation:

For this exercise let's use Faraday's Law

emf =
`- (d \phi)/(dt)` - d fi / dt

`\phi` = B. A

\phi = B A cos θ

The bold are vectors. It indicates that the area of the body is A = 0.046 m², the magnetic field B = 1.4 T, also iindicate that the normal to the area is parallel to the field, therefore the angle θ = 0 and cos 0 =1.

suppose a linear change of the magnetic field

emf = - A
`(B_f - B_o)/( \Delta t)`

Dt = - A
`(B_f - B_o)/(emf)`

the final field before a fault is zero

let's calculate

Δt = - 0.046 (0- 1.4) / 0.011

Δt = 5.85 s