Question

How many particles are in 9.58 x 1023 of potassium sulfate (K2SO4)? (5.77 x 1047 particles)

Answer 1

`5.77x10^(47)particles.`

Step-by-step explanation:

Hello!

In this case, since we are given 9.58x10²³ moles of potassium sulfate, it is possible to compute the particles according to the Avogadro's number:

6.022x10²³

As shown below:

`9.58x10^(23)mol*(6.022x10^(23))/(1mol)\\\\5.77x10^(47)particles.`

Best regards!