Question

A piece of metal is cooled in a water calorimeter. This process increases the water temperature by 7.0°C. How much energy is lost if there is 100. g of water in the calorimeter? (specific heat of water is 4.184 J/g°C)

Answer 1

Heat changes

Q = m.c.Δt

Q = 100 g x 4.184 J/g°C x 7 °C

Q = 2928.8 J