Answer:
y= -(1/6)x -2
Explanation:
We know:
y= mx +b is the general equation of the line
Was given:
y= 6x +3, has the slope m=6
Find the equation of the line
y= -(1/6)x + b, perpendicular lines have their slope negative reciprocal m=-1/6
Find the y-intercept that is b
for point (x=12, y= -4) the equation of our line becomes
-4 = -(1/6)(12) + b, multiply a fraction and a number (a/b)*c = ab/c
-4 = -12/6 +b, simplify the fraction
-4 = -2 + b , add 2 to both sides
-4+2 = -2+2 +b , solve for b
-2 = b
The equation of the line that passes through the point (12,-4) and is perpendicular to the line with the equation y=6x +3 is :
y= -(1/6)x -2