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A jar contains n nickels and d dimes. There is a total of 206 coins in the jar. The value of the coins is $13.95. How many nickels and how many dimes are in the jar? ​

1 Answer

10 votes

Answer:

73 dimes and 133 nickels

Explanation:

$13.95 = 1395 cents

5n + 10d = 1395 (since each nickel is 5 cents and each dime is 10 cents)

5n = 1395 - 10d (subtract 10d from both sides to solve for n)

n = 279 - 2d

n + d = 206

279 - 2d + d = 206 (substitute n with the previous expression)

279 - d = 206 (add variable d and -2d)

-d = -73 (solve for d and divide both sides by negative 1)

d = 73

n + 73 = 206 (solve for n and subtract both sides by 73)

n = 133

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