Question

(x-1)(x-3)(x+5)(x+7)=297

Answer 1

x=4

Explanation:

(4-1)(4-3)(4+5)(4+7)=297

Answer 2

First simplify the expression into polynomial form,

`(x-1)(x-3)(x+5)(x+7)=297`

`x^4+8x^3-10x^2-104x+105=297`

`x^4+8x^3-10x^2-104x-192=0`

Now factor into,

`(x-4)(x+8)(x^2+4x+6)=0`

Which means the solutions are,

`x-4=0\implies\boxed{x_1=4}`

`x+8=0\implies\boxed{x_2=-8}`

and then two complex solutions because determinant of the third factor
`D\lt0`,

`x^2+4x+6=0`

`x^2+4x+4=-2`

`(x+2)^2=-2\implies\boxed{x_3=i√(2)-2},\boxed{x_4=-i√(2)-2}`

Hope this helps :)