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The center of a circle bs located at 3,9), and the evde hesa vedles that to sustain What the parengtame een hee) 0 #4 - 6 = 46 + 6 = () 7* 9-6-167-15-6 0676x* 167 18-0 D. ** *64…

The center of a circle bs located at 3,9), and the evde hesa vedles that to sustain What the parengtame een hee) 0 #4 - 6 = 46 + 6 = () 7* 9-6-167-15-6 0676x* 167 18-0 D. ** *64…
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The center of a circle bs located at 3,9), and the evde hesa vedles that to sustain What the parengtame een hee)

0 #4 - 6 = 46 + 6 = ()
7* 9-6-167-15-6
0676x* 167 18-0
D. ** *64*167-15-0

The center of a circle bs located at 3,9), and the evde hesa vedles that to sustain-example-1
User Ratiorick
by
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1 Answer

14 votes

Answer:

The general equation of a circle is x2 + y2 - 6x - 16y + 48 = 0

Explanation:

User JKHA
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