Question

Prove that angle ADC is congruent to angle CBA

with solution!

Answer 1

Explanation:

< i'll use this too represent angle

this is only presuming that this is a parallelogram and i also don't know what those numbers mean

< ACB = < CAD (alt <s of DA II CB) A

< ACD = < CAB (alt <s of DC II AB) A

AB is common S

therefore, ∆ADC is congruent to ∆CBA

if ∆ADC is congruent to ∆CBA

then < ADC = < CBA