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Evaluate [x + 1/y]^m × [x-1/y]^n /[y+1/x]^m [y-1/x]^n​

Evaluate [x + 1/y]^m × [x-1/y]^n /[y+1/x]^m [y-1/x]^n​-example-1
User William Worley
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1 Answer

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Answer:

(x/y)^(m+n)

Explanation:


\displaystyle(\left(x+(1)/(y)\right)^m\left(x-(1)/(y)\right)^n)/(\left(y+(1)/(x)\right)^m\left(y-(1)/(x)\right)^n)=\left((x)/(y)\right)^m\left((x)/(y)\right)^n\\\\=\boxed{\left((x)/(y)\right)^(m+n)}

User Soramimo
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