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32 votes
32 votes
Steve plans to use 28 feet of fencing to enclose a region of his yard for a pen for his pet rabbit. What is the area, in square feet, of the largest rectangular region Steve can enclose?

Can anyone also tell me what area of math this is and what I should study?

User Cenk Alti
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2.6k points

2 Answers

11 votes
11 votes

Final answer:

The largest rectangular area Steve can enclose with 28 feet of fencing is a square with an area of 49 square feet, by dividing the total perimeter by 4 to get the length of each side of the square.

Step-by-step explanation:

Steve plans to use 28 feet of fencing to enclose a rectangular region for his pet rabbit. To find the largest area that Steve can enclose, we need to use the properties of rectangles. The problem can be solved by recognizing that a square is the rectangle with the maximum area for a given perimeter. This is a concept in mathematics that deals with perimeter and area optimization.

Given a fixed perimeter of 28 feet, each side of the square will be 28 feet divided by 4, which is 7 feet. The area of this square, which is side length times side length, will be 7 feet × 7 feet = 49 square feet. Therefore, the largest rectangular area Steve can enclose with 28 feet of fencing is 49 square feet. This falls into the category of geometry and optimization in mathematics.

User Pierre Baret
by
2.7k points
27 votes
27 votes

Answer: 4 (length) x 7 (width) = 28 sq. ft.

User Stuyvenstein
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2.8k points
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