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Thomas Jefferson School is building a new basketball court as seen below in orange. The blueprint is missing a dimension. 50 feet 17 inches 94 feet 37.6 inches Note: Drawing may not be to scale What should the width of the blueprint be?​

Thomas Jefferson School is building a new basketball court as seen below in orange-example-1
User Scatman
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1 Answer

14 votes

Answer: ap.617 in

Explanation:

To determine the width of the basketball court on the blueprint, we need to convert the given measurements from feet and inches to a single unit of measurement. Let's convert the measurements to inches to make the calculations easier.

- The given length of 50 feet and 17 inches can be converted to inches as follows: 50 feet x 12 inches/foot + 17 inches = 600 inches + 17 inches = 617 inches.

- The given width of 94 feet and 37.6 inches can be converted to inches as follows: 94 feet x 12 inches/foot + 37.6 inches = 1128 inches + 37.6 inches = 1165.6 inches.

Now that we have the measurements in inches, we can find the width of the blueprint.

Since the blueprint is missing a dimension, we can assume that it represents the actual basketball court proportionally. Therefore, we can set up a proportion using the known length and width measurements:

617 inches (length on the blueprint) / x (width on the blueprint) = 1165.6 inches (actual length) / 94 feet + 37.6 inches (actual width).

To solve for x (the width on the blueprint), we can cross-multiply and divide:

x = (617 inches * (94 feet + 37.6 inches)) / 1165.6 inches.

Calculating this, we get:

x ≈ (617 * (94*12 + 37.6)) / 1165.6 ≈ (617 * (1128 + 37.6)) / 1165.6 ≈ (617 * 1165.6) / 1165.6 ≈ 617 inches.

Therefore, the width of the basketball court on the blueprint should be approximately 617 inches.

User Shamese
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