Question

13. PLEASE HELP ME

The area of a playground is 336 yd2. The width of the playground is 5 yd longer than its length. Find the length and width of the playground.

A. length = 16 yd, width = 21 yd

B. length = 21 yd, width = 26 yd

C. length = 21 yd, width = 16 yd

D. length = 26 yd, width = 21 yd

Answer 1

1. Find out which one has the width 5 yd longer
2. It is A and B
3. Multiply both
16x21= 336. 21x26=546
4. See which one equals 336
5. It is option A
6. Your answer is option A

Answer 2

• Let length be x
• width=x+5

We know

`\boxed{\sf Area=Length* Width}`

• Putting values

`\\ \sf\longmapsto 336=x(x+5)`

`\\ \sf\longmapsto x^2+5x=336`

`\\ \sf\longmapsto x^2+5x-336=0`

• Using mid term split

`\\ \sf\longmapsto x^2-16x+21x-336=0`

`\\ \sf\longmapsto x(x-16)+21(x-16)=0`

`\\ \sf\longmapsto (x-16)(x+21)=0`

`\\ \sf\longmapsto (x-16)=0\:or\:(x+21)=0`

`\\ \sf\longmapsto x=16\:or\:x=-21`

• Ignore negative value

`\\ \sf\longmapsto Length=x=16yd`

`\\ \sf\longmapsto Width=x+5=16+5=21yd`

Option a is correct