Answer:
Energy Saved = 6.93 x 10⁹ Btu
Cost Saved = $ 30145.5
Step-by-step explanation:
The energy generated by each boiler can be given by the following formula:
![Annual\ Energy = (Heat\ In)(Combustion\ Efficiency)(Operating\ Hours)](https://img.qammunity.org/2022/formulas/engineering/college/81am9wpeqjojkktqpkbykynb8wnbnrf34g.png)
Now, the energy saved by the increase of efficiency through tuning will be the difference between the energy produced before and after tuning:
![Energy\ Saved = (Heat\ In)(Efficiency\ After\ Tune - Efficiency\ Before\ Tune)(Hours)](https://img.qammunity.org/2022/formulas/engineering/college/c5ll2io2uf9hgovhoh0fgygmjfouk5ukbt.png)
![Energy\ Saved = (5.5\ x\ 3\ x\ 10^(6)\ Btu/h)(0.8-0.7)(4200\ h)](https://img.qammunity.org/2022/formulas/engineering/college/8ll63oroeb2g1745kgex43fdj2245uwnfq.png)
Energy Saved = 6.93 x 10⁹ Btu
Now, for the saved cost:
![Cost\ Saved = (Energy\ Saved)(Unit\ Cost)\\Cost\ Saved = (6.93\ x\ 10^(9)\ Btu)(\$4.35/10^(6)Btu)\\](https://img.qammunity.org/2022/formulas/engineering/college/ahospaqitrgjvrs4dackzvnruef2jy3njz.png)
Cost Saved = $ 30145.5