Question

Solving the quadratic equation 3x^2+12x=-14 by quadratic formula

Answer 1

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Answer:

x = -2 ±i(√6)/3

Explanation:

The formula for the solution of ax²+bx+c=0 is ...

`x=(-b\pm√(b^2-4ac))/(2a)`

When your equation is written in standard form, it is ...

3x² +12x +14 = 0

so the values needed in the formula are a=3, b=12, c=14.

`x=(-12\pm√(12^2-4(3)(14)))/(2(3))=(-12\pm√(-24))/(6)=(-12\pm2i√(6))/(6)\\\\\boxed{x=-2\pm(√(6))/(3)i}`