Question

Rewrite the expression as the algebraic expression in x
Sin
(tan^-1(x))

Answer 1

9514 1404 393

Answer:

sin(tan^-1(x)) = x/√(x² +1)

Explanation:

We know that for an angle in a right triangle...

Tan = Opposite/Adjacent

and

Sin = Opposite/Hypotenuse

so we can let Opposite = x and Adjacent = 1. The Pythagorean theorem tells us that ...

Hypotenuse² = Opposite² + Adjacent² = x² +1

Then the sine of the angle is ...

sin(tan^-1(x)) = x/√(x² +1)