Question

Factor completely 12a^3d^2 – 6ad^3

Answer 1

`12a^3d^2-6ad^3`

To factor an integer, we need to divide it by the ascending sequence of primes 2, 3, 5

In the end, the number of times each prime divides the original integer becomes its exponent.

Prime number 2 to the power of 2 equals 4 .

Prime number 3 to the power of 1 equals 3 .

`2^(2) * 3* a^(3) * b^(2) -(2*3)ad^(3)`

Result:-
`6ad^2\left(2a^2-d\right)`

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