Question

A cone has a radius of 6.2 mm and a height of 10.8 mm. What is the volume of the cone to the nearest tenth? use π = 3.14

Answer 1

The volume of the cone with a radius of 6.2 mm and a height of 10.8 mm is 434.2 mm^3 when rounded to the nearest tenth using the formula V = (1/3)πr²h and π = 3.14.

Step-by-step explanation:

The volume of a cone is calculated using the formula V = (1/3)\(πr^2h\), where \(π\) is the constant Pi (approximately 3.14), r is the radius of the cone's base, and h is the height of the cone. In this case, the cone has a radius (r) of 6.2 mm and a height (h) of 10.8 mm. Using these values, the volume of the cone to the nearest tenth can be calculated as follows:

1. First, square the radius: r^2 = (6.2 mm)^2 = 38.44 mm^2.
2. Then, multiply the result by the height: r^2 × h = 38.44 mm^2 × 10.8 mm.
3. Next, multiply this result by Pi (π): π × r^2 × h = 3.14 × 38.44 mm^2 × 10.8 mm = 1302.7152 mm^3.
4. Finally, divide by 3 to find the volume of the cone: V = (1/3) × 1302.7152 mm^3 = 434.2384 mm^3.

To get the answer to the nearest tenth, round 434.2384 mm^3 to 434.2 mm^3.

Answer 2

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Actually Welcome to the Concept of the volumes.

Here given as, r= 6.2 mm, h = 10.8 mm, π=3.14

hence, the volume of the cone is

Volume = 1/3(πr^2h)

===> vol = 1/3(3.14*(6.2)^2*(10.8))

==> Vol = 1/3*(1303.57)

==> Vol = 434.52 mm^3

Hence the volume of the cone is 434.52 mm^3