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24 votes
24 votes
Integrate[Exp[Power[sinx,2]]sin2x,x]

User John Pittaway
by
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1 Answer

12 votes
12 votes

Answer:

e^{sin²x}+c

Explanation:


\int e^(sin^2x) sin 2x dx=?

is this statement?

if so

then


put~sin^2x=t\\differentiate\\2 sin ~x~cos~x~dx=dt\\sin~2x ~dx=dt\\\int e^t~dt=e^t+c\\=e^(sin^2x)+c

User Jsmartt
by
2.9k points