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25 votes
25 votes
Solve for x

(x-5) ²+5 =49

User Danwilkie
by
2.7k points

2 Answers

25 votes
25 votes

Answer:


\left(x-5\right)^2+5=49

Subtract 5 from both sides


\left(x-5\right)^2+5-5=49-5


\left(x-5\right)^2=44


x-5=√(44)


44=2^(2) *11


x-5=√(11) \sqrt{2^(2) }

Radical rule:-
\sqrt[n]{a^(n) } =a


x-5=2√(11)

Add 5 to both sides


x=2√(11)+5

-------


x-5=-2√(11)

Add 5 to both sides


x-5=-2√(11)

Ans:
x=2√(11)+5,\:x=-2√(11)+5

OAmalOHopeO

User Jlmt
by
2.6k points
8 votes
8 votes

Answer:

x = 5±2 sqrt(11)

Explanation:

(x-5) ²+5 =49

Subtract 5 from each side

(x-5) ²+5-5 =49-5

(x-5) ² =44

Take the square root of each side

sqrt((x-5) ²) =±sqrt(44)

sqrt((x-5) ²) =±sqrt(4*11)

x-5 = ±2 sqrt(11)

Add 5 to each side

x-5+5 = 5±2 sqrt(11)

x = 5±2 sqrt(11)

User Vincenzo
by
2.7k points