Explanation:
Hi there!
From the question;
The slope of the line is 5/10 or 0.5.
Also the equation of the line passes through the point (0,5).
Note: Use one point formula. {i.e (y-y1)=m(x-x1)}
So, use the formula here and keep the values;
(y-5) = 5/10(x-0)
or, 10(y-5) = 5x
or, 10y-50 = 5x
or, 5x - 10y +50 = 0
Therefore, the required equation is 5x - 10y +50 = 0 or x-2y+10 = 0.
Hope it helps!